Produit Indice Logarithmique [ 0.301 ÷ 1.618 = 0.18603213844 ]
Un exemple avec [C2] 65.406 Hz
65.406 Hz [C2] * 0.18603213844 = 12.1676180468 [ constante (K) fréquentielle (Hz) du PIL ]
f substrat * 0.18603213844 = K → f
(65.406 * 0.301) /1.618 + 65.406 = 77.573618047 Hz
f° + ( K → f * 1, 2, 3….., et ainsi…)
65.406 + (12.1676180468 * 1) = 77.5736180468 Hz ~ (1200 * log(77.5736180468 / 65.406)) / log(2) = 295 ∆ = cents
65.406 + (12.1676180468 * 2) = 89.7412360936 Hz ~ (1200 * log(89.7412360936 / 65.406)) / log(2) = 548 ∆
65.406 + (12.1676180468 * 3) = 101.90885414 Hz ~1200 * log(101.90885414 / 65.406)) / log(2) = 768 ∆
65.406 + (12.1676180468 * 4) = 114.076472187 Hz ~ (1200 * log(114.076472187 / 65.406)) / log(2) = 963 ∆
65.406 + (12.1676180468 * 5) = 126.244090234 Hz ~ (1200 * log(126.244090234 / 65.406))/ log(2) = 1138 ∆
65.406 + (12.1676180468 * 6) = 138.411708281 Hz ~ (1200 * log(138.411708281 / 65.406)) / log(2) = 1298 ∆
65.406 + (12.1676180468 * 7) = 150.579326328 Hz ~ (1200 * log(150.579326328/65.406)) / log(2) = 1144 ∆
65.406 + (12.1676180468 * 8) = 162.746944374 Hz ~ (1200 * log(162.746944374 / 65.406)) / log(2) = 1578 ∆
65.406 + (12.1676180468 * 9) = 174.914562421 Hz ~ (1200 * log(174.914562421 / 65.406)) / log(2) =1703 ∆
65.406 + (12.1676180468 * 10) =187.082180468 Hz ~ (1200 * log(187.082180468 / 65.406)) / log(2) = 1819 ∆
65.406 + (12.1676180468 * 11) =199.249798515 Hz ~ (1200 * log(199.249798515 / 65.406)) / log(2) = 1929 ∆
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65.406 + (12.1676180468 * 55) = 734.624992574 Hz ~ (1200 * log(734.624992574 / 65.406))/ log(2)
= 4187.41570383 ∆ [espace frontière flottante]
Réalité sonore
Déploiement résiduelle Fibonacci / Sauveur
Cents & Suite de Fibonacci
Et encore une autre formulation…
⇔ Anexo J. Sauveur